NE406 Radiation Protection and Shielding
|
Homework #10:Use Table C.1 to answer the following questions:1. For water, what fraction of the total thermal cross section is due to the oxygen? What fraction of the absorption cross section? 2. a. What thickness of U238 would have the same penetration characteristics
(macroscopic total times thickness) for thermal neutrons as 30 cm of water?
(Use 1 g/cc for water and 19 g/cc for U238).
|
|
Return to Course Outline © 1998 by Ronald E. Pevey. All rights reserved. |